500x^2-300x+44,8=0

Solution for 500x^2-300x+44,8=0 equation:

500x^2-300x+44.8=0

a = 500; b = -300; c = +44.8;
Δ = b2-4ac
Δ = -3002-4·500·44.8
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-20}{2*500}=\frac{280}{1000}
=7/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+20}{2*500}=\frac{320}{1000}
=8/25
$